Check a Sparse Matrix

#include<stdio.h>

int main()
{

    int m,n, i,j, d,a[10][10];
    int count = 0;
    printf("\nEnter the number of rows and columns of the matrix \n\n");
    scanf("%d%d",&m,&n);

    printf("\nEnter the %d elements of the matrix \n\n", m*n);
    for(i = 0; i< m; i++)
    {
        for(j = 0; j< n; j++)
        {
            scanf("%d", &a[i][j]);
            if(a[i][j] == 0)
                count++;
        }
    }


    printf("\n\nThe entered matrix is: \n\n");
    for(i = 0; i < m; i++)
    {
        for(j= 0; j< n; j++)
        {
            printf("%d\t", a[i][j]);
        }
        printf("\n");
    }


    if(count > (m*n)/2)
        printf("\n\nThe entered matrix is a sparse matrix\n\n");
    else
        printf("\n\nThe entered matrix is not a sparse matrix\n\n");


    return 0;
}

 

       

Note: Need to be arranged in compiler after copied

 

 OutPut:

Enter the number of rows and columns of the matrix 3 3 Enter the 9 elements of the matrix 2 3 9 0 0 0 0 0 2 The entered matrix is: 2 3 9 0 0 0 0 0 2 The entered matrix is a sparse matrix