Check A Number Armstrong Or Not

#include<stdio.h> 

int main()
{

    int n,num,sum,digit;

    printf("Enter a Number:\n");
    scanf("%d",&n);
    num=n;
    sum=0;

    while(n!=0)
    {
         digit=n%10;
         sum=sum+digit*digit*digit;
         n=n/10;
    }
    if(num==sum)
    {   printf("The Sum no %d is an armstrong number",num);
    }
    else
    {   printf("The Sum no %d is not an armstrong number",num);
    }

    return 0;
}

     

           

Note: Need to be arranged in compiler after copied

   

 OutPut:

Enter a Number: 153 The Sum no 153 is an armstrong number